(-2x/z^2)^5 - solution

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Solution for (-2x/z^2)^5 equation:

D( x )

z^2 = 0

z^2 = 0

z^2 = 0

z^2 = 0

x naleu017Cy do R

x belongs to the empty set

((-2*x)/(z^2))^5 = 0

x belongs to the empty set

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